5p^2-27p-56=0

Solution for 5p^2-27p-56=0 equation:

5p^2-27p-56=0

a = 5; b = -27; c = -56;
Δ = b2-4ac
Δ = -272-4·5·(-56)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-43}{2*5}=\frac{-16}{10}
=-1+3/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+43}{2*5}=\frac{70}{10}
=7
$